(3x^3+2x^2-4x)+(3x^2+2x-4)=0

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Solution for (3x^3+2x^2-4x)+(3x^2+2x-4)=0 equation: 


Simplifying
(3x3 + 2x2 + -4x) + (3x2 + 2x + -4) = 0

Reorder the terms:
(-4x + 2x2 + 3x3) + (3x2 + 2x + -4) = 0

Remove parenthesis around (-4x + 2x2 + 3x3)
-4x + 2x2 + 3x3 + (3x2 + 2x + -4) = 0

Reorder the terms:
-4x + 2x2 + 3x3 + (-4 + 2x + 3x2) = 0

Remove parenthesis around (-4 + 2x + 3x2)
-4x + 2x2 + 3x3 + -4 + 2x + 3x2 = 0

Reorder the terms:
-4 + -4x + 2x + 2x2 + 3x2 + 3x3 = 0

Combine like terms: -4x + 2x = -2x
-4 + -2x + 2x2 + 3x2 + 3x3 = 0

Combine like terms: 2x2 + 3x2 = 5x2
-4 + -2x + 5x2 + 3x3 = 0

Solving
-4 + -2x + 5x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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